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:iconmonochromatic-stains:

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The area between Brinstar and Maridia. :bucktooth:


Can you see the apollian gasket?


I support constructive criticism. :#1:

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:iconkagitsune:
Alas, I cannot quite make out the entire Apollonian gasket, but I can see its iterative structure in some of the corners... Oh, wait, there it is! 8D *feels smart*

An excellent image. I love the effect: it's like being near a bubbling spring in a cave... with a mysterious light source from below... ^w^v

--
直美 :: honest beauty ::
カギツネ :: A misspelled baby fox
:iconmonochromatic-stains:
This actually failed in some parts. :noes:

Thanks though!

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FAQ #39: How to get more pageviews?

#hangintherebaby whore. :meow:
:iconrakshiv-fire-runner:
I'm not going to lie, I haven't the faintest what an apollonian gasket is, which isn't to say I love the piece, which I do. I like how it resembles oil underneath water, faint whisps of...something...escaping into the water above.
:iconthe-final-i:
-escapes from the apollonian gasket before it gets him-

Ok, I don't want to think about what I'd thought an Apollonian gasket was.

For some reason those really sharp parts look really awkward to me, and I'd have rathered that the rest of the image were a wee bit sharper. Overall, this is still pretty nice.

To my space-wracked brain this looks like some sort of weirdass star with a solar flare erupting and shooting away into the depths of space.

Brinstar depths? well, I guess my view's completely different from what you had in mind then.

:P

--
:
E^2= (p^2c^2)+([Δm^2]c^4)
which implies that
E= [mc^2]/[<sq. root>1-(v^2/c^2)]
when p=0 (in eq 1, or in 2 rearranged to 1])
E=mc^2
[as rest mass cannot be attained, p can never=0, so E should, not always be calculated as = mc^2].
:iconmonochromatic-stains:
Well, Google "Apollian Gasket" if you don't know what it is.

What is your view?

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FAQ #39: How to get more pageviews?

#hangintherebaby whore. :meow:
:iconthe-final-i:
Oh I did.

You don't want to know what I'd thought it was. :dead:

--
:
E^2= (p^2c^2)+([Δm^2]c^4)
which implies that
E= [mc^2]/[<sq. root>1-(v^2/c^2)]
when p=0 (in eq 1, or in 2 rearranged to 1])
E=mc^2
[as rest mass cannot be attained, p can never=0, so E should, not always be calculated as = mc^2].
:icontsukinohikari20:
There's a tad bit of ghosting going on and some weird depth of field as well, but it sort of gives off the look you have when looking into vapor.

Sort of like it warps your vision. And distorts it. I like the feeling you captured as well.

Beautiful fractal :D

--
*Apophysis
Join my group, Fractal Alliance

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March 19, 2008
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